document.write( "Question 69283This question is from textbook Algebra 1
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document.write( ": I am having difficulty with this problem - please help me if you can. The chapter is Solving Linear Systems by Linear Combinations (substitution not allowed).\r
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document.write( " 2q = 7 - 5p
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document.write( " 4p - 16 = q\r
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document.write( "I am using the 5 step formula - arrange like terms in columns, obtain coefficients that are opposites for one variable, add equations & eliminate one variable & solve, etc... I did nine other problems this way and solved them. I don't see what I'm doing wrong with this one. Any help will be appreciated.
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Algebra.Com's Answer #49314 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2q = 7 - 5p \n" ); document.write( " 4p - 16 = q \n" ); document.write( "-------------- \n" ); document.write( "Rearrange: \n" ); document.write( "1st: 5p+2q=7 \n" ); document.write( "2nd: 4p-q=16 \n" ); document.write( "--------------- \n" ); document.write( "Multiply 2nd by 2 to get: \n" ); document.write( "3rd: 8p-2q=32 \n" ); document.write( "Add 1st and 3rd to get: \n" ); document.write( "13p=39 \n" ); document.write( "p=3 \n" ); document.write( "------------ \n" ); document.write( "Substitute that into 2nd to get: \n" ); document.write( "4*3-q=16 \n" ); document.write( "q=-4 \n" ); document.write( "------------ \n" ); document.write( "Solution: p=3; q=-4 \n" ); document.write( "Check in 1st: 5p+2q=7 \n" ); document.write( "5*3+2*-4 = 7 \n" ); document.write( "7=7 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |