document.write( "Question 819351: Each Saturday, Sarah and Beccy drive from the town of Littlesburgh to the city of Bigsford to go shopping. The last time they made the journey, Sarah set off at 8:15 am, travelling at 30mph. Beccy set off at 8:27 am but was travelling at 50mph.
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\n" ); document.write( "Assuming they remain at these speeds and do not stop, at what time does Beccy overtake Sarah, and how far away were they both from Littlesburgh?
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Algebra.Com's Answer #493098 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
How much of a head start did Sarah get?
\n" ); document.write( "\"+d%5B1%5D+=+30%2A%2812%2F60%29+=+6+\" miles
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\n" ); document.write( "Start a stopwatch when Becky leaves
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\n" ); document.write( "Let \"+d+\" = the distance that Becky travels
\n" ); document.write( "until she catches Sarah.
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\n" ); document.write( "Let \"+t+\" = the time on the stopwatch when
\n" ); document.write( "Becky catches Sarah.
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\n" ); document.write( "Equation for Sarah:
\n" ); document.write( "(1) \"+d+-+6+=+30t+\"
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\n" ); document.write( "Equation for Becky:
\n" ); document.write( "(2) \"+d+=+50t+\"
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\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+50t+-+6+=+30t+\"
\n" ); document.write( "(1) \"+20t+=+6+\"
\n" ); document.write( "(1) \"+t+=+3%2F10+\" hrs
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\n" ); document.write( "\"+%283%2F10%29%2A60+=+18+\" min
\n" ); document.write( "Becky overtakes Sarah at 8:27 + 18 min = 8:45
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\n" ); document.write( "(2) \"+d+=+50t+\"
\n" ); document.write( "(2) \"+d+=+50%2A%283%2F10%29+\"
\n" ); document.write( "(2) \"+d+=+15+\"
\n" ); document.write( "They are 15 miles from Littlesburgh
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\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+6+=+30t+\"
\n" ); document.write( "(1) \"+15+-+6+=+30%2A%283%2F10%29+\"
\n" ); document.write( "(1) \"+9+=+9+\"
\n" ); document.write( "OK
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