document.write( "Question 819293: A triangle ABC has sides with lengths a= 12 cm, b = 8 cm, and the angle B = 30º. What are the possible values for the length c of the third side of the triangle? \n" ); document.write( "
Algebra.Com's Answer #493080 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
ABC could be XBC OR YBC. vertex A could be X or Y, then side b (AB) would be XC or YC, measuring 8cm.
\n" ); document.write( "Since there were two possible triangles, I drew a third triangle, right triangle BCD.
\n" ); document.write( "CD = BC\"sin%2830%5Eo%29=12%2A0.5=6\"
\n" ); document.write( "We can also calculate
\n" ); document.write( "BD = BC\"cos%2830%5Eo%29=12%2A%28sqrt%283%29%2F2%29=6sqrt%283%29=about10.39\"
\n" ); document.write( "We can calculate the length of XD = YD in congruent right triangles XDC and YDC.
\n" ); document.write( "That length is
\n" ); document.write( "XD = YD =\"sqrt%288%5E2-6%5E2%29sqrt%2864-36%29=sqrt%2828%29=2sqrt%287%29=about5.29\"
\n" ); document.write( "Then,
\n" ); document.write( "BX = BD - XD =\"highlight%286sqrt%283%29-2sqrt%287%29%29\"= about\"highlight%285.10%29\"
\n" ); document.write( "BY = BD + YD =\"highlight%286sqrt%283%29%2B2sqrt%287%29%29\"= about\"highlight%2815.68%29\"
\n" ); document.write( "So the approximate measure of the third side is
\n" ); document.write( "either \"highlight%285.10cm%29\" or \"highlight%2815.68cm%29\" .
\n" ); document.write( "
\n" ); document.write( "ALTERNATE SOLUTION:
\n" ); document.write( "Maybe your teacher expected you to use law of cosines,
\n" ); document.write( "\"b%5E2=a%5E2%2Bc%5E2-2ac%2Acos%28B%29\"
\n" ); document.write( "\"8%5E2=12%5E2%2Bc%5E2-2%2A12%2Ac%2Acos%2830%5Eo%29\"
\n" ); document.write( "\"64=144%2Bc%5E2-2%2A12%2Ac%2A%28sqrt%283%29%2F2%29\"
\n" ); document.write( "\"64=144%2Bc%5E2-%2812sqrt%283%29%29c\"
\n" ); document.write( "\"c%5E2-%2812sqrt%283%29%29c%2B144-64=0\"
\n" ); document.write( "\"c%5E2-%2812sqrt%283%29%29c%2B80=0\"
\n" ); document.write( "That quadratic equation can be solved using the quadratic formula:
\n" ); document.write( "
\n" ); document.write( "The quadratic equation can also be solved by completing the square:
\n" ); document.write( "\"c%5E2-%2812sqrt%283%29%29c%2B80=0\"
\n" ); document.write( "\"c%5E2-%2812sqrt%283%29%29c=-80\"
\n" ); document.write( "\"c%5E2-%2812sqrt%283%29%29c%2B%286sqrt%283%29%29%5E2=%286sqrt%283%29%29%5E2-80\"
\n" ); document.write( "\"%28c-6sqrt%283%29%29%5E2=6%5E2%2A3-80\"
\n" ); document.write( "\"%28c-6sqrt%283%29%29%5E2=108-80\"
\n" ); document.write( "\"%28c-6sqrt%283%29%29%5E2=28\" so ,
\n" ); document.write( "leading to the solutions \"highlight%28c=6sqrt%283%29+%2B-+2sqrt%287%29%29\"
\n" ); document.write( "
\n" ); document.write( "ANOTHER ALTERNATE:
\n" ); document.write( "Since you have the measures of angle B and side b, you can apply law of sines, and find \"sin%28A%29\", and two possible approximate measures for angle A.
\n" ); document.write( "Then you could calculate the approximate measures for the two options for angle C, and for \"sin%28C%29\", and then use law of sines again to find the two possible measures for side c.
\n" ); document.write( "
\n" );