document.write( "Question 819247: -3/10a^2+20a-80=a/5a-10+1/2a+8
\n" ); document.write( "Please show me how to solve for \"a\"
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Algebra.Com's Answer #493036 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
-3/10a^2+20a-80=a/5a-10+1/2a+8 means \"-3%2F10a%5E2%2B20a-80=a%2F5a-10%2B1%2F2a%2B8\"
\n" ); document.write( "That would be a weird, difficult problem.
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\n" ); document.write( "I suspect you meant
\n" ); document.write( "-3/(10a^2+20a-80)=a/(5a-10)+1/(2a+8)
\n" ); document.write( "which you would write as
\n" ); document.write( "\"-3%2F%2810a%5E2%2B20a-80%29=a%2F%285a-10%29%2B1%2F%282a%2B8%29\"
\n" ); document.write( "when writing on paper,
\n" ); document.write( "or maybe you would write it as \"%28-3%29%2F%2810a%5E2%2B20a-80%29=a%2F%285a-10%29%2B1%2F%282a%2B8%29\"
\n" ); document.write( "(It's the same, but the minus sign next to the 3 may be more convenient).
\n" ); document.write( "That is the problem I will solve for you.
\n" ); document.write( "First, you need to realize that
\n" ); document.write( "\"%285a-10%29%282a%2B8%29=10a%5E2%2B40a-20a-80=10a%5E2%2B20a-80\" .
\n" ); document.write( "You could use \"10a%5E2%2B20a-80\" as your common denominator.
\n" ); document.write( "(If your teacher likes that way of working through the problem, you may want to humor the teacher).
\n" ); document.write( "Another option is to multiply both sides of the equal sign times
\n" ); document.write( "\"%285a-10%29%282a%2B8%29=10a%5E2%2B20a-80\" .
\n" ); document.write( "Multiplying both sides of the equal sign times a number or expression gives you an equivalent equation,
\n" ); document.write( "EXCEPT if the number or expression is zero.
\n" ); document.write( "I would just multiply without worrying now, and later check the solutions found.
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\n" ); document.write( "\"-3=a%285a-10%29%282a%2B8%29%2F%285a-10%29%2B1%285a-10%29%282a%2B8%29%2F%282a%2B8%29\"
\n" ); document.write( "\"-3=a%282a%2B8%29%2B%285a-10%29\"
\n" ); document.write( "\"-3=2a%5E2%2B8a%2B5a-10\"
\n" ); document.write( "\"0=2a%5E2%2B13a-10%2B3\"
\n" ); document.write( "\"2a%5E2%2B13a-7=0\"
\n" ); document.write( "Now we have to solve that quadratic equation.
\n" ); document.write( "I would use factoring, starting by looking for factor pairs that multiply to give \"2%2A%28-7%29=-14\" and add up to \"13\" .
\n" ); document.write( "\"14%2A%28-1%29=-14\" and \"14%2A%28-1%29=13\" so I re-write the equation as
\n" ); document.write( "\"2a%5E2%2B14a-a-7=0\" and then factor by grouping:
\n" ); document.write( "\"%282a%5E2-a%29%2B%2814a-7%29=0\"
\n" ); document.write( "\"a%282a-1%29%2B7%282a-1%29=0\"
\n" ); document.write( "\"%28a%2B7%29%282a-1%29=0\"
\n" ); document.write( "and the solutions happen when
\n" ); document.write( "\"a%2B7=0\" --> \"highlight%28a=-7%29\" or
\n" ); document.write( "\"2a-1=0\" --> \"highlight%28a=1%2F2%29\"
\n" ); document.write( "Neither one of those solutions makes \"%285a-10%29%282a%2B8%29=10a%5E2%2B20a-80\" equal to zero,
\n" ); document.write( "so we should accept those solutions, but it is good to verify.
\n" ); document.write( "Verification:
\n" ); document.write( "For \"a=-7\" ,
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\n" ); document.write( "For \"a=1%2F2\" ,
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\n" ); document.write( "\n" ); document.write( "IMPORTANT NOTE:
\n" ); document.write( "The long horizontal bar above \"10a%5E2%2B20a-80\" is a grouping symbol.
\n" ); document.write( "It means that there are understood, invisible parentheses wrapping up, as separate packages,
\n" ); document.write( "what's on top of the line,
\n" ); document.write( "and whats below the line.
\n" ); document.write( "When typing math, you need to type those parentheses,
\n" ); document.write( "as required by the internationally agreed upon order of operations rules.
\n" ); document.write( "If you don't you will not be understood.
\n" ); document.write( "You probably, will get the wrong results,
\n" ); document.write( "and reporting wrong results will get you in trouble.
\n" ); document.write( "(As an analytical chemist, I know that).
\n" ); document.write( "(100-25)/(100+25)=\"%28100-25%29%2F%28100%2B25%29=75%2F125=3%2F5=0.6\" ,
\n" ); document.write( "but if you type 100-25/100+25=\"100-25%2F100%2B25=100-0.25%2B25=124.75\"
\n" ); document.write( "most calculators will give you the correct answer as \"124.75\" .
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