document.write( "Question 819340: ......................................................................
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document.write( "A man has 10 gallons of a 50% sulphuric acid mixture, and 20 gallons of a 20% solution, and 5 gallons of a 10% solution. He wants to use up all the 10% solution and make 15 gallons of 30% solution. How much of each solution should he use? \n" );
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Algebra.Com's Answer #493035 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A man has 10 gallons of a 50% sulphuric acid mixture, and 20 gallons of a 20% solution, and 5 gallons of a 10% solution. He wants to use up all the 10% solution and make 15 gallons of 30% solution. How much of each solution should he use? \n" ); document.write( "--------------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid + acid = acid \n" ); document.write( "----- \n" ); document.write( "0.10*5 + 0.50*x + 0.20(10-x) = 0.30*15 \n" ); document.write( "------- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "10*5 + 50x + 20*10-20x = 30*15 \n" ); document.write( "-------- \n" ); document.write( "50 + 30x + 200 = 450 \n" ); document.write( "30x = 200 \n" ); document.write( "x = 20/3 = 6 2/3 gallons (amt. of 50% solution needed) \n" ); document.write( "10-x = 3 1/3 gallons (amt. of 20% solution needed) \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |