document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69253>Question 69253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 cm more than 2 times its width.  If the area of the rectangle is 74 cm2, find the dimensions of the rectangle to the nearest thousandth.\r<BR>\n" );
document.write( "\n" );
document.write( "The answer that I have figured is w=5.165 and L=14.330 and I have no idea if this is correct. Can I get a little help with this problem. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49302 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I WOULD SAY THAT YOU ARE RIGHT ON THE MONEY ON THIS PROBLEM.  GOOD WORK!!!!\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Let x= the width of the rectangle<BR>\n" );
document.write( "Then 2x+4=length of rectangle (4 cm more than twice the width)\r<BR>\n" );
document.write( "\n" );
document.write( "Area of rectangle =l*w=(2x+4)(x) so our equation to solve is:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282x%2B4%29%28x%29=74 ALIGN=MIDDLE  ALT=\"%282x%2B4%29%28x%29=74\"   DISABLED_style= \"max-width:90%; height:auto;\" >  get rid of parens\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B4x=74 ALIGN=MIDDLE  ALT=\"2x%5E2%2B4x=74\"   DISABLED_style= \"max-width:90%; height:auto;\" >  subtract 74 from both sides\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2%2B4x-74=0 ALIGN=MIDDLE  ALT=\"2x%5E2%2B4x-74=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >  divide both sides by 2\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B2x-37=0 ALIGN=MIDDLE  ALT=\"x%5E2%2B2x-37=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >  quadratic in standard form\r<BR>\n" );
document.write( "\n" );
document.write( "We'll solve using the quadratic formula:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A%28-37%29+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A%28-37%29+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2+%2B-+sqrt%28152+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-2+%2B-+sqrt%28152+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2+%2B-+sqrt%28152+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-2+%2B-+sqrt%28152+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2+%2B-12.330+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-2+%2B-12.330+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-2+%2B12.330+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-2+%2B12.330+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%2810.330+%29%29%2F%282%29+ ALIGN=MIDDLE  ALT=\"x+=+%2810.330+%29%29%2F%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=5.165 ALIGN=MIDDLE  ALT=\"x=5.165\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm -----------------width of rectangle\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B4=2%2A5.165%2B4=14.330 ALIGN=MIDDLE  ALT=\"2x%2B4=2%2A5.165%2B4=14.330\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm---------------length of rectangle\r<BR>\n" );
document.write( "\n" );
document.write( "We'll discount the negative value for x\r<BR>\n" );
document.write( "\n" );
document.write( "CK\r<BR>\n" );
document.write( "\n" );
document.write( "Area = l*w=14.330*5.165=74.01~74 ---ok\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps----ptaylor\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );