document.write( "Question 819213: Mikayla went on a 60 mile trip to a soccer game. On the way back, due to road construction she had to drive 8 miles per hour slower. This made the trip take 10 hours longer. How fast did she drive to the soccer game? \n" ); document.write( "
Algebra.Com's Answer #492986 by mananth(16946)\"\" \"About 
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let speed to go be x\r
\n" ); document.write( "\n" ); document.write( "time = 60/x\r
\n" ); document.write( "\n" ); document.write( "time to return \r
\n" ); document.write( "\n" ); document.write( "speed = (x-8)
\n" ); document.write( "d=60\r
\n" ); document.write( "\n" ); document.write( "time = 60/(x-8)\r
\n" ); document.write( "\n" ); document.write( "return time - to go time = 10 hours\r
\n" ); document.write( "\n" ); document.write( "60/(x-8)-60/x=10\r
\n" ); document.write( "\n" ); document.write( "LCD = x(x-8)\r
\n" ); document.write( "\n" ); document.write( "(60x-60(x-8))/x(x-8)=10\r
\n" ); document.write( "\n" ); document.write( "60x-60x+480=10x(x-8)\r
\n" ); document.write( "\n" ); document.write( "480=10x^2-80x\r
\n" ); document.write( "\n" ); document.write( "10x^2-80x-480=0
\n" ); document.write( "/10
\n" ); document.write( "x^2-8x-48=0\r
\n" ); document.write( "\n" ); document.write( "x2-12x+4x-48=0\r
\n" ); document.write( "\n" ); document.write( "(x-12)(x+4)=0\r
\n" ); document.write( "\n" ); document.write( "x=12 OR -4
\n" ); document.write( "speed cannot be negative\r
\n" ); document.write( "\n" ); document.write( "speed going is 12 mph\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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