document.write( "Question 819077: What would the ordered pair be for x-3y=2 and 3x-7y=4. Here is the work that I have done so far. x-3y=2 Then I got y by itself by subtracting x on both sides so I got -3y=-x+2. Then I divided -3y by itself on both sides. So I got y=1/3x-2/3. Then I plugged y into the equation x-3y=2. Once I plugged it in I got x-3(1/3x-2/3)=2. Once I solved that I got x-x-2=2. Then I added 2 on each side to get x-x=4 Then I solved that to get 0x=4 and I didn't know what I did wrong. So I double checked myself to see if I got a different answer. This is what I did; I plugged y into the equation 3x-7y=4 and got 3x-7(1/3x-2/3)=4. Then I distributed and got 3x-(7/3x-14/3=4. After this I got lost and didn't know what to do. If you can help that'd be great! Thanks! \n" ); document.write( "
Algebra.Com's Answer #492976 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "What would the ordered pair be for x-3y=2 and 3x-7y=4. Here is the work that I have done so far. x-3y=2 Then I got y by itself by subtracting x on both sides so I got -3y=-x+2. Then I divided -3y by itself on both sides. So I got y=1/3x-2/3. Then I plugged y into the equation x-3y=2. Once I plugged it in I got x-3(1/3x-2/3)=2. Once I solved that I got x-x-2=2. Then I added 2 on each side to get x-x=4 Then I solved that to get 0x=4 and I didn't know what I did wrong. So I double checked myself to see if I got a different answer. This is what I did; I plugged y into the equation 3x-7y=4 and got 3x-7(1/3x-2/3)=4. Then I distributed and got 3x-(7/3x-14/3=4. After this I got lost and didn't know what to do. If you can help that'd be great! Thanks!\r
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\n" ); document.write( " x - 3y = 2 ----- eq (i)
\n" ); document.write( "3x - 7y = 4 ----- eq (ii)\r
\n" ); document.write( "\n" ); document.write( "Seems as though you want to solve this using substitution.
\n" ); document.write( "Well, you don't have to go through all of that. You can just simply solve eq (i) for x, and substitute that into
\n" ); document.write( "eq (ii). In other words: x - 3y = 2 becomes: x = 2 + 3y, or x = 3y + 2, which can be substituted into eq (ii) to
\n" ); document.write( "determine the value of y. Then substitute this y-value into any of the two equations to determine the value of x. \r
\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "Further help is available, online or in-person,for a fee, obviously. \r
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