document.write( "Question 818997: A perimeter of a triangle is 49 cm. The first side is 2 cm less than twice the second side,and the third side is 3 cm longer than the second side. Find the lenght of each side. \n" ); document.write( "

Algebra.Com's Answer #492921 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "A perimeter of a triangle is 49 cm. The first side is 2 cm less than twice the second side,and the third side is 3 cm longer than the second side. Find the lenght of each side.\r
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document.write( "Let length of second side be S
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document.write( "Then length of first side is: 2S - 2, and length of third side is: S + 3
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document.write( "Thus, S + 2S - 2 + S + 3 = 49
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document.write( "Solve this to determine S, or the second side. Thereafter, make the necessary substitutions to find the other two sides.\r
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document.write( "Then do a check!! \r
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