document.write( "Question 818988: A bus is traveling 15 mph slower than an 18 wheeler. In the time it takes the bus to travel 190 miles, the 18-wheeler travels 135 miles. Find the speed of both the bus and the 18-wheeler. \n" ); document.write( "
Algebra.Com's Answer #492902 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Speed of truck is r.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "__________________speed_____________time____________distance
\n" ); document.write( "Bus_______________r-15______________(___)___________190
\n" ); document.write( "Truck_____________r_________________(___)___________135\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We need time expressions for the equal time of both bus and truck:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "__________________speed_____________time____________distance
\n" ); document.write( "Bus_______________r-15______________190/(r-15)___________190
\n" ); document.write( "Truck_____________r_________________135/r___________135\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You should already sense a mistake in the given information. Equal time, the bus is slower but traveled more miles than the truck. This cannot be. You mixed-up some information.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"190%2F%28r-15%29=135%2Fr\"
\n" ); document.write( "LCD r(r-15)
\n" ); document.write( "or
\n" ); document.write( "\"135%28r-15%29=190r\"
\n" ); document.write( "\"135r-135%2A15=190r\"
\n" ); document.write( "\"135r-190r=135%2A15\"
\n" ); document.write( "\"-55r=135%2A3%2A5\"
\n" ); document.write( "\"r=-%28135%2A3%2A5%29%2F%2811%2A5%29=-135%2A3%2F11\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Why should we allow \"r%3C0\"?
\n" ); document.write( "
\n" ); document.write( "
\n" );