document.write( "Question 818979: I am trying to solve a system of equations with three variables.
\n" ); document.write( "6x-y+2z=-14
\n" ); document.write( "x+2y-z=-2
\n" ); document.write( "2x+2y-3z=-11\r
\n" ); document.write( "\n" ); document.write( "I am new to algebra and have never done an equation with three variables. I know I am supposed to take two of the equations so that I can eliminate one variable, such as x, but I am unsure on which two I should choose. If anyone can help me solve this, and show me each step in doing so it would be appreciated. Thanks
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Algebra.Com's Answer #492890 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "I. 6x-y+2z=-14
\n" ); document.write( "II. x+2y-z=-2
\n" ); document.write( "III. 2x+2y-3z=-11 \r
\n" ); document.write( "\n" ); document.write( "I. 12x-2y+4z=-28 |Multiplying EQ I by 2 & adding I an II to eliminate y
\n" ); document.write( "II. x+2y-z=-2
\n" ); document.write( " A \"13x+%2B+3z+=+-30\"
\n" ); document.write( "II. -x-2y+z=2 |Multiplying EQ II by -1 & adding II an III to eliminate y
\n" ); document.write( "III. 2x+2y-3z=-11
\n" ); document.write( " B \"x+-+2z+=+-9\"\r
\n" ); document.write( "\n" ); document.write( " \"13x+%2B+3z+=+-30\"
\n" ); document.write( " \"-13x+%2B26z+=+117\" |Multiplying EQ B by -13
\n" ); document.write( " 29z = 87
\n" ); document.write( " z = 3 and x = -3 and y = 2
\n" ); document.write( " 2x+2y-3z=-11
\n" ); document.write( " -6 + 4 - 9 = -11 \n" ); document.write( "
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