document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=818866>Question 818866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi there, how can I find an equation of th line containing (2,-1) and parallel to y=1/3× + 2?\r<BR>\n" );
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document.write( "I need help solving for u: 5u^2-50=0\r<BR>\n" );
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document.write( "How can I solve for x? 2÷×+2=5÷2×-1\r<BR>\n" );
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document.write( "Rationalizing denominator: -5÷3 square root 2 + 6\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492842 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there, how can I find an equation of th line containing (2,-1) and parallel to y=1/3× + 2? <BR>\n" );
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document.write( "Form: y = mx + b<BR>\n" );
document.write( "m = (1/3)<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "y = -1<BR>\n" );
document.write( "Solve for \"b\":<BR>\n" );
document.write( "-1 = 2*2 + b<BR>\n" );
document.write( "b = -5<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = (1/3)x - 5<BR>\n" );
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document.write( "I need help solving for u: <BR>\n" );
document.write( "5u^2-50=0<BR>\n" );
document.write( "Divide thru by 5 to get:<BR>\n" );
document.write( "u^2 - 10 = 0<BR>\n" );
document.write( "u^2 = 10<BR>\n" );
document.write( "u = sqrt(10) or u = -sqrt(10)<BR>\n" );
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document.write( "How can I solve for x? 2÷×+2=5÷2×-1 <BR>\n" );
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document.write( "2/(x+2) = 5/(2x-1)<BR>\n" );
document.write( "Cross-multiply to get:<BR>\n" );
document.write( "4x-2 = 5x+10<BR>\n" );
document.write( "x = -12<BR>\n" );
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document.write( "Rationalizing denominator: -5÷3 square root 2 + 6 <BR>\n" );
document.write( "-5/(3sqrt(2) + 6)<BR>\n" );
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document.write( "Multiply numerator and denominator by 3sqrt(2)-6 to get:<BR>\n" );
document.write( "[-5(3sqrt(2)-6)]/[(3sqrt(2)+6)(3sqrt(2)-6)]<BR>\n" );
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document.write( "= [-15sqrt(2)+30]/[(3sqrt(2))^2-6^2]<BR>\n" );
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document.write( "[-15sqrt(2)-30] / [9*2-36]<BR>\n" );
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document.write( "= (-15sqrt(2)-30) / (-18)<BR>\n" );
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document.write( "= (5/6)sqrt(2)+ (5/3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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