document.write( "Question 818644:
\n" ); document.write( "find the domain of f(x)=log(x-5) squared \n" ); document.write( "
Algebra.Com's Answer #492818 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
The answer depend on what is being squared. Is it
\n" ); document.write( "\"f%28x%29=%28log%28%28x-5%29%29%29%5E2\"
\n" ); document.write( "or
\n" ); document.write( "\"f%28x%29=log%28%28%28x-5%29%5E2%29%29\"?
\n" ); document.write( "Since I don't know which is right I cannot solve the problem. But I can tell you what to do. The arguments of all logarithms must be positive. So the solution will be whatever x-values will make the argument positive. So:
  • If the first equation is correct, then argument is x-5. The domain will be the solution to:
    \n" ); document.write( "x - 5 > 0
  • If the second equation is correct, then the argument is \"%28x-5%29%5E2\".. The domain will be the solution to:
    \n" ); document.write( "\"%28x-5%29%5E2+%3E+0\"
    \n" ); document.write( "Note: Since squaring something never results in a negative, the only x's that are not in the domain are the x's that make \"%28x-5%29%5E2\" zero. So an alternate way to find the domain is to solve:
    \n" ); document.write( "\"%28x-5%29%5E2+=+0\"
    \n" ); document.write( "and then the domain is all real numbers except the solution(s) to the equation above.

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