document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=818772>Question 818772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x=e^y-e^(-y)/e^y+e^(-y) then prove that y=logeroot1+x/1-x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492817 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What the heck is \"logeroot1\"???<br><BR>\n" );
document.write( "Please re-post your question and use parentheses and/or some English to make the expression clear. For example: y = base 8 log of (the cube root of ((1+x)/(1-x))) would describe:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+log%288%2C+%28root%283%2C+%281%2Bx%29%2F%281-x%29%29%29%29+ ALIGN=MIDDLE  ALT=\"y+=+log%288%2C+%28root%283%2C+%281%2Bx%29%2F%281-x%29%29%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Or you could teach yourself algebra.com's syntax for formulas. Click on the \"Show source\" link above to see what I typed to make that equation display like that. </SPAN>\n" );
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