document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=818810>Question 818810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Raymond left his home by car, traveling on a certain road at the rate of 30mph. Two hours later, his brother Arthur left home and started after him on the same road, traveling at the rate of 45mph. how many hours did Arthur overtake Raymond? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492814 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Raymond left his home by car, traveling on a certain road at the rate of 30mph. Two hours later, his brother Arthur left home and started after him on the same road, traveling at the rate of 45mph. how many hours did Arthur overtake Raymond?\r<BR>\n" );
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document.write( "Raymond -rate of 30mph.<BR>\n" );
document.write( "Arthur - rate of 45mph.<BR>\n" );
document.write( "travelling in same direction so subtract speeds= catch up speed<BR>\n" );
document.write( "45-30=15 mph\r<BR>\n" );
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document.write( "In 2 hours Raymond travels 60 miles\r<BR>\n" );
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document.write( "t= catch up distance / catch up speed\r<BR>\n" );
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document.write( "60/15=\r<BR>\n" );
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document.write( "=4 hours\r<BR>\n" );
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document.write( " </SPAN>\n" );
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