document.write( "Question 818708: Graph the following polynomials functions and label the zeros and y-intercepts:
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document.write( "a) f(x)=x^2(x-1)(x-5)\r
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document.write( "b) f(x)=(x-3)(x^2-36)(x+2)
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document.write( "Please I need to solve this problem! \n" );
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Algebra.Com's Answer #492811 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! I'll do problem \"b\": \n" ); document.write( " \n" ); document.write( "This will be easier to do if we finish factoring. The middle factor is a difference of squares. So we can use that pattern to factor it: \n" ); document.write( " \n" ); document.write( "For the x-intercepts we make the y equal to zero and solve for x: \n" ); document.write( " \n" ); document.write( "Since we have a product equal to zero, one of the factors must be zero. Perhaps you can see what x values these would be. (If not, then set each factor equal to zero (x-3 = 0 or x+6 = 0 or ...) and solve.) They are: \n" ); document.write( "x = 3 or x = -6 or x = 6 or x = -2 \n" ); document.write( "So the x-intercepts are: (3, 0), (-6, 0), (6, 0) and (-2, 0) \n" ); document.write( "For the y-intercept, make the x zero: \n" ); document.write( " \n" ); document.write( "which simplifies ... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the y-intercept is (0, 216) \n" ); document.write( "The graph might be difficult to sketch with just these intercepts. You probably want to try to build a table of values using different x-vales so you have additional points. FWIW, here's a rough sketch (with different scales on the x and y axes so you can see the most interesting parts): \n" ); document.write( " \n" ); document.write( "The problem in part a is already fully factored. So it should be easier than part b. \n" ); document.write( " |