document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=818788>Question 818788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3. <BR>\n" );
document.write( "Write log3^15 - log3^10 as a single logarithm.\r<BR>\n" );
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document.write( "A. 	log3^3 <BR>\n" );
document.write( "B. 	log3^3/2<BR>\n" );
document.write( "C. 	log3^2 <BR>\n" );
document.write( "D. 	log3^3 - log3^2 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492802 by </B><A HREF=/tutors/aboutme.mpl?userid=Bobb><B>Bobb(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Bobb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log3^15-log3^10<BR>\n" );
document.write( "firstly,we start by recalling the law of logarithm relating to this problem,<BR>\n" );
document.write( "log(P/Q)=logP-logQ<BR>\n" );
document.write( "then,<BR>\n" );
document.write( "log3^15-log3^10=log3^(15/10)<BR>\n" );
document.write( "on dividing,we get<BR>\n" );
document.write( "Log3^(3/2).ans </SPAN>\n" );
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