document.write( "Question 818627: fine the asymptotes of the hyperbola given by x^2/16-y^2/36=1 \n" ); document.write( "
Algebra.Com's Answer #492796 by lwsshak3(11628)\"\" \"About 
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Find the asymptotes of the hyperbola given by
\n" ); document.write( "x^2/16-y^2/36=1
\n" ); document.write( "Given equation is that of a hyperbola with horizontal transverse axis and center at the origin (0,0)
\n" ); document.write( "Asymptotes are straight lines that go through the center and take the standard form: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "slopes of asymptotes for hyperbolas with horizontal transverse axis=±b/a
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "a^2=16
\n" ); document.write( "a=√16=4
\n" ); document.write( "b^2=36
\n" ); document.write( "b=√36=6
\n" ); document.write( "slopes of asymptotes=±b/a=±6/4=±3/2
\n" ); document.write( "equation of asymptote with positive slope:
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=3x/2+b
\n" ); document.write( "since asymptote goes thru center (0,0), b=0
\n" ); document.write( "so, y=3x/2
\n" ); document.write( "..
\n" ); document.write( "equation of asymptote with negative slope:
\n" ); document.write( "y=-3x/2
\n" ); document.write( "
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