document.write( "Question 818627: fine the asymptotes of the hyperbola given by x^2/16-y^2/36=1 \n" ); document.write( "
Algebra.Com's Answer #492796 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the asymptotes of the hyperbola given by \n" ); document.write( "x^2/16-y^2/36=1 \n" ); document.write( "Given equation is that of a hyperbola with horizontal transverse axis and center at the origin (0,0) \n" ); document.write( "Asymptotes are straight lines that go through the center and take the standard form: y=mx+b, m=slope, b=y-intercept \n" ); document.write( "slopes of asymptotes for hyperbolas with horizontal transverse axis=±b/a \n" ); document.write( "For given hyperbola: \n" ); document.write( "a^2=16 \n" ); document.write( "a=√16=4 \n" ); document.write( "b^2=36 \n" ); document.write( "b=√36=6 \n" ); document.write( "slopes of asymptotes=±b/a=±6/4=±3/2 \n" ); document.write( "equation of asymptote with positive slope: \n" ); document.write( "y=mx+b \n" ); document.write( "y=3x/2+b \n" ); document.write( "since asymptote goes thru center (0,0), b=0 \n" ); document.write( "so, y=3x/2 \n" ); document.write( ".. \n" ); document.write( "equation of asymptote with negative slope: \n" ); document.write( "y=-3x/2 \n" ); document.write( " |