document.write( "Question 818653: If you were to walk around the perimeter of a particular building, you would cover 2476 ft. If this rectangular building is 166 ft longer than it is wide, what are its dimensions?\r
\n" ); document.write( "\n" ); document.write( "I know the equation P = 2L + 2W, so I think it would be something like 2476 2L + 2(W+166). At least, that's what I've tried from there. But I don't know what to do next.
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Algebra.Com's Answer #492750 by jhunjiro(67)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Given:
\n" ); document.write( "P=2476
\n" ); document.write( "L=166+W\r
\n" ); document.write( "\n" ); document.write( "Solution
\n" ); document.write( "-
\n" ); document.write( "P=2L +2W
\n" ); document.write( "2476 = 2L + 2W
\n" ); document.write( "2476 = 2(166+W) + 2W
\n" ); document.write( "2476 = 332 + 2W + 2W
\n" ); document.write( "2476 -332 = 4W
\n" ); document.write( "2144=4W\r
\n" ); document.write( "\n" ); document.write( "W=536\r
\n" ); document.write( "\n" ); document.write( "L= 166+W
\n" ); document.write( "L= 166+536
\n" ); document.write( "L= 702\r
\n" ); document.write( "\n" ); document.write( "Final Answer:
\n" ); document.write( "L=702\r
\n" ); document.write( "\n" ); document.write( "W=536
\n" ); document.write( "
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