document.write( "Question 818653: If you were to walk around the perimeter of a particular building, you would cover 2476 ft. If this rectangular building is 166 ft longer than it is wide, what are its dimensions?\r
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document.write( "I know the equation P = 2L + 2W, so I think it would be something like 2476 2L + 2(W+166). At least, that's what I've tried from there. But I don't know what to do next. \n" );
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Algebra.Com's Answer #492750 by jhunjiro(67)![]() ![]() You can put this solution on YOUR website! - \n" ); document.write( "Given: \n" ); document.write( "P=2476 \n" ); document.write( "L=166+W\r \n" ); document.write( "\n" ); document.write( "Solution \n" ); document.write( "- \n" ); document.write( "P=2L +2W \n" ); document.write( "2476 = 2L + 2W \n" ); document.write( "2476 = 2(166+W) + 2W \n" ); document.write( "2476 = 332 + 2W + 2W \n" ); document.write( "2476 -332 = 4W \n" ); document.write( "2144=4W\r \n" ); document.write( "\n" ); document.write( "W=536\r \n" ); document.write( "\n" ); document.write( "L= 166+W \n" ); document.write( "L= 166+536 \n" ); document.write( "L= 702\r \n" ); document.write( "\n" ); document.write( "Final Answer: \n" ); document.write( "L=702\r \n" ); document.write( "\n" ); document.write( "W=536 \n" ); document.write( " |