document.write( "Question 818689: It is necessary to have a 40% antifreeze solution in the radiator of a certain car. The radiator now has 50 liters of 20% solution. How many liters of this should be drained and replaced with 100% antifreeze to get the desired strength? \n" ); document.write( "
Algebra.Com's Answer #492736 by TimothyLamb(4379)\"\" \"About 
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(50 - v)(0.20) + v(1.00) = 50(0.40)
\n" ); document.write( "50(0.20) - v(0.20) + v(1.00) = 20
\n" ); document.write( "10 + v(0.80) = 20
\n" ); document.write( "v(0.80) = 10
\n" ); document.write( "v = 12.5
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\n" ); document.write( "answer:
\n" ); document.write( "drain 12.5 liters from the radiator, then add 12.5 liters of 100% antifreeze
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