document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69182>Question 69182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose you just have enough dimes and quarters to pay for a loaf of bread and a  quart of milk, which cost $3.45. you have a total of 15 dimes and quarters.\r<BR>\n" );
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document.write( "let d = the number of dimes you have<BR>\n" );
document.write( "let q = the number of quarters you have\r<BR>\n" );
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document.write( "a. write a system of equations that models the information given above.<BR>\n" );
document.write( "b. solve the system for the number of dimes and quarters you have.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49269 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D+Q=15 D=15-Q NOW SUBSTITUTE (15-Q) FOR D IN THE SECOND EQUATION<BR>\n" );
document.write( "10D+25Q=345<BR>\n" );
document.write( "10(15-Q)+25Q=345<BR>\n" );
document.write( "150-10Q+25Q=345<BR>\n" );
document.write( "15Q=345-150<BR>\n" );
document.write( "15Q=195<BR>\n" );
document.write( "Q=195/15<BR>\n" );
document.write( "Q=13 NUMBER OF QUARTERS.<BR>\n" );
document.write( "D+13=15<BR>\n" );
document.write( "D=15-13<BR>\n" );
document.write( "D=2 NUMBER OF DIMES<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "10*2+25*13=345<BR>\n" );
document.write( "20+325=345<BR>\n" );
document.write( "345=345 </SPAN>\n" );
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