document.write( "Question 818621: how much of an alloy that is 30 copper should be mixed with 100 ounces that is 70% copper in order to get an alloy that is 50% copper \n" ); document.write( "
Algebra.Com's Answer #492681 by TimothyLamb(4379)\"\" \"About 
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a = weight of 30% copper allow
\n" ); document.write( "w = weight of final mixture
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\n" ); document.write( "30a + 70(100) = 50w
\n" ); document.write( "w = 100 + a
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\n" ); document.write( "30a + 7000 = 50w
\n" ); document.write( "30a + 7000 = 50(100 + a)
\n" ); document.write( "30a + 7000 = 5000 + 50a
\n" ); document.write( "20a = 2000
\n" ); document.write( "a = 100
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\n" ); document.write( "answer:
\n" ); document.write( "mix in 100 ounces of 30% copper alloy
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