document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=813523>Question 813523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a team of 4 is to be choosen at random from 5 women and 6 men.in how many ways can this be done if <BR>\n" );
document.write( "a.  there are no restrictions.<BR>\n" );
document.write( "b.  there must be more men than women. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492661 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can use the counting principle:\r<BR>\n" );
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document.write( "a) 11 people, choose 4...11*10*9*8=7920<BR>\n" );
document.write( "b) more men than women means 3 men... (6*5*4)(5*4)=2400 </SPAN>\n" );
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