document.write( "Question 818472: The rectangle has been broken into four smaller rectangles. The area of three
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document.write( "of the smaller rectangles are shown below. Find the area of the fourth one.
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document.write( "234
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document.write( "312
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document.write( "270
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document.write( "x \n" );
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Algebra.Com's Answer #492636 by KMST(5328)![]() ![]() You can put this solution on YOUR website! You must have a drawing to go with the problem. \n" ); document.write( "Otherwise, there could be a lot of answers. \n" ); document.write( "See NOTE 1 below. \n" ); document.write( " \n" ); document.write( "If your drawing looks like this: \n" ); document.write( " \n" ); document.write( "You know that one of the small rectangles (rectangle A in my drawing) \n" ); document.write( "has the same width as a second small rectangle (B), and the same length as a third small rectangle (C). \n" ); document.write( "If the width and length measures are whole numbers, \n" ); document.write( "A could measure 18 by 13, with \n" ); document.write( "B could measure 24 by 13, with \n" ); document.write( "C could measure 18 by 15, with \n" ); document.write( "In that case, the 4th small rectangle measures 24 by 15, \n" ); document.write( "with are area of \n" ); document.write( "That is one possible solution. \n" ); document.write( " \n" ); document.write( "How do we figure that? \n" ); document.write( "Factoring. \n" ); document.write( "The possible factorings for the areas are: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "No we look for common factors. \n" ); document.write( "One of those area values is the area of rectangle A. \n" ); document.write( "One of the factorings must have \n" ); document.write( "one factor in common with the factoring for the area of B, and \n" ); document.write( "the other factor in common with the factoring for the area of C. \n" ); document.write( "We look for common factors, like \n" ); document.write( "which appears in \n" ); document.write( "Since we find \n" ); document.write( "also as a factor of the third area value, \n" ); document.write( "we know that the small rectangles could be as I described above, \n" ); document.write( "a \n" ); document.write( "a \n" ); document.write( "a \n" ); document.write( " \n" ); document.write( "However, it could also be that A is \n" ); document.write( " \n" ); document.write( "a \n" ); document.write( "a \n" ); document.write( "That would make the 4th small rectangle \n" ); document.write( "a \n" ); document.write( "Or it could be that A is \n" ); document.write( " \n" ); document.write( "a \n" ); document.write( "a \n" ); document.write( "That would make the 4th small rectangle \n" ); document.write( "a \n" ); document.write( "In all cases we end up with area= \n" ); document.write( "We could prove why is that with a little algebra, \n" ); document.write( "but maybe all that was expected is one possible set of dimensions and/or the result. \n" ); document.write( " \n" ); document.write( "NOTE 1: \n" ); document.write( "Let's say your drawing looks like this: \n" ); document.write( " \n" ); document.write( "That is a different problem, and may have more than one solution. \n" ); document.write( "At least you know that two of the smaller rectangles have the same width, \n" ); document.write( "and that their lengths add up to the length of the large rectangle. \n" ); document.write( " \n" ); document.write( "It could even be a more complicated picture, where none of the rectangles have obvious common dimensions. \n" ); document.write( " \n" ); document.write( "I considered those possibilities, but my bet is that your problem is the one I solved above. If that's not the case, ask again. \n" ); document.write( " \n" ); document.write( "NOTE 2: \n" ); document.write( "When you post a problem, here or anywhere, try not to leave out important information, like a drawing that comes with the problem. \n" ); document.write( "Also, when your problem is not answered here because it is too difficult, the child-geniuses in the forum of artofproblemsolving.com can solve it. Just do not expect a very detailed explanation, and do not \"insult\" them by posting a problem that is too easy for the level where you post it. For example, I would post this problem at the middle school level, or at the most basic high school level. \n" ); document.write( " |