document.write( "Question 818520: verify the identity by simplifying the left side
\n" );
document.write( "sin^2x-sin^2y=cos^2y-cos^2x \n" );
document.write( "
Algebra.Com's Answer #492610 by jhunjiro(67)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Given \n" ); document.write( "sin^2x-sin^2y=cos^2y-cos^2x\r \n" ); document.write( "\n" ); document.write( "Solution: \n" ); document.write( "Pythagorean Identity \n" ); document.write( " cos^2x + sin^2y = 1 \n" ); document.write( " sin^2Ø = 1 - cos^2Ø \n" ); document.write( " \n" ); document.write( " sin^2x-sin^2y=cos^2y-cos^2x \n" ); document.write( " (1-cos^2x)-(1 - cos^2y)=cos^2y-cos^2x \n" ); document.write( " 1 -cos^2x -1 + cos^2y =cos^2y-cos^2x \n" ); document.write( " 1 -1 -cos^2x + cos^2y =cos^2y-cos^2x \n" ); document.write( " -cos^2x + cos^2y =cos^2y-cos^2x\r \n" ); document.write( "\n" ); document.write( " cos^2y - cos^2x =cos^2y-cos^2x \n" ); document.write( " \n" ); document.write( " |