document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=818526>Question 818526</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If area and perimeter of a rectangles are 120 sq m and 46m then what r the dimensions of a rectangle ....ans is 15 and 8 bt dont know how to solve it </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492608 by </B><A HREF=/tutors/aboutme.mpl?userid=jhunjiro><B>jhunjiro(67)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jhunjiro><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jhunjiro><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your Answer:<BR>\n" );
document.write( "Given:<BR>\n" );
document.write( "Area=120 sq m<BR>\n" );
document.write( "Perimeter=46 meter<BR>\n" );
document.write( "Solution:<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "-<BR>\n" );
document.write( "(46 = 2L+2W)/2<BR>\n" );
document.write( "23 = L+W<BR>\n" );
document.write( "L = 23-W\r<BR>\n" );
document.write( "\n" );
document.write( "Area= L x W<BR>\n" );
document.write( "120 = LxW<BR>\n" );
document.write( "120 = (23-W)x (W)<BR>\n" );
document.write( "120 = 23W-W^2<BR>\n" );
document.write( "W^2 - 23W + 120 = 0<BR>\n" );
document.write( "(W-15)(W-8) = 0<BR>\n" );
document.write( "W-15=0<BR>\n" );
document.write( "W = 15<BR>\n" );
document.write( "L = 23-W<BR>\n" );
document.write( "L = 23-15<BR>\n" );
document.write( "L = 8<BR>\n" );
document.write( "Final Answer: 15 and 8.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );