document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=818450>Question 818450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle the two larger angles differ by 10 degrees. The smaller angle is 50 degrees less than the largest angle. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492577 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = largest angle<BR>\n" );
document.write( "x - 10 = medium angle<BR>\n" );
document.write( "x - 50 = smallest angle\r<BR>\n" );
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document.write( "x + x - 10 + x - 50 = 180 {angles of a triangle add up to 180°}<BR>\n" );
document.write( "3x - 60 = 180 {combined like terms}<BR>\n" );
document.write( "3x = 240 {added 60 to each side}<BR>\n" );
document.write( "x = 80 {divided each side by 4}<BR>\n" );
document.write( "x - 10 = 70 {substituted 80, in for x, into x - 10}<BR>\n" );
document.write( "x - 50 = 30 {substituted 80, in for x, into x - 50}\r<BR>\n" );
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document.write( "80°, 70°, and 30° are the measures of the angles<BR>\n" );
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