document.write( "Question 818289: log5(3x+7) + log5(x-5)= 2 \n" ); document.write( "

Algebra.Com's Answer #492545 by LinnW(1048) $\"\"$ $\"About$

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log5(3x+7) + log5(x-5)= 2log5(5)\r
\n" ); document.write( "\n" ); document.write( "log5(3x+7) + log5(x-5)= log5(5^2)
\n" ); document.write( "log5( (3x+7)/(x-5) ) = log5(25)\r
\n" ); document.write( "\n" ); document.write( " $\"%283x%2B7%29%2F%28x-5%29++=+25%2F1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%283x%2B7%29++=+25%28x-5%29\"$
\n" ); document.write( " $\"3x%2B7++=+25x-125%29\"$
\n" ); document.write( "Subtract 3x from each side.
\n" ); document.write( " $\"7++=+22x-125%29\"$
\n" ); document.write( "Add 125 to each side.
\n" ); document.write( "132 = 22x
\n" ); document.write( " 6 = x \n" ); document.write( "

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