document.write( "Question 818362: Hi!
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document.write( "I am a little lost with the problem \" how many gallons of pure antifreeze must be mixed with 30 gallons of 15% antifreeze to get a mixture that is 40% antifreeze\" \r
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document.write( "So far I have multiplied 30 x .15 to get 4.5 gallons of pure antifreeze but am not sure where to go after that. \r
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document.write( "Thanks!
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document.write( "Rachel \n" );
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Algebra.Com's Answer #492479 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many gallons of pure antifreeze must be mixed with 30 gallons of 15% antifreeze to get a mixture that is 40% antifreeze\" \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "alch + alch = alch \n" ); document.write( "-------- \n" ); document.write( "0.15*30 + 1*x = 0.40(30+x) \n" ); document.write( "-------- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "15*30 + 100x = 40*30 + 40x \n" ); document.write( "------ \n" ); document.write( "60x = 25*30 \n" ); document.write( "x = 12.5 gallons (amt. of pure solution needed) \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |