document.write( "Question 818362: Hi!
\n" ); document.write( "I am a little lost with the problem \" how many gallons of pure antifreeze must be mixed with 30 gallons of 15% antifreeze to get a mixture that is 40% antifreeze\" \r
\n" ); document.write( "\n" ); document.write( "So far I have multiplied 30 x .15 to get 4.5 gallons of pure antifreeze but am not sure where to go after that. \r
\n" ); document.write( "\n" ); document.write( "Thanks!
\n" ); document.write( "Rachel
\n" ); document.write( "

Algebra.Com's Answer #492479 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
how many gallons of pure antifreeze must be mixed with 30 gallons of 15% antifreeze to get a mixture that is 40% antifreeze\"
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\n" ); document.write( "Equation:
\n" ); document.write( "alch + alch = alch
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\n" ); document.write( "0.15*30 + 1*x = 0.40(30+x)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "15*30 + 100x = 40*30 + 40x
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\n" ); document.write( "60x = 25*30
\n" ); document.write( "x = 12.5 gallons (amt. of pure solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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