document.write( "Question 69199: Please help me solve for a for this equation: \"+.95a%2B.3-.33a=.22%2B3a++\".
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Algebra.Com's Answer #49247 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
.95a+.3-.33a=.22+3a
\n" ); document.write( ".95a-.33a-3a=-.3+.22
\n" ); document.write( "-2.38a=-.08
\n" ); document.write( "a=-.08/-2.38
\n" ); document.write( "a=.0336134
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