document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=818109>Question 818109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve x for log(3x-1)=1<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492342 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note: I'm assuming that this log has a default base of 10.\r<BR>\n" );
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document.write( "log(3x-1)=1\r<BR>\n" );
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document.write( "3x-1=10^1\r<BR>\n" );
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document.write( "3x-1=10\r<BR>\n" );
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document.write( "3x=10+1\r<BR>\n" );
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document.write( "3x=11\r<BR>\n" );
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document.write( "x=<font color=\"red\">11/3</font> </SPAN>\n" );
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