document.write( "Question 818080: one jet travels 30 mi/h faster than another jet. Both jets left Atlanta, traveling in opposite directions, at 9:00 am. At noon they were 2490 apart. Find their rates. \n" ); document.write( "
Algebra.Com's Answer #492334 by mananth(16946)\"\" \"About 
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let the rate of one jet be x
\n" ); document.write( "other will be x+30\r
\n" ); document.write( "\n" ); document.write( "they are moving away from each other
\n" ); document.write( "so add up speeds
\n" ); document.write( "x+x+30=2x+30 mph\r
\n" ); document.write( "\n" ); document.write( "d=2490\r
\n" ); document.write( "\n" ); document.write( "t= 3 hours\r
\n" ); document.write( "\n" ); document.write( "3(2x+30)=2490\r
\n" ); document.write( "\n" ); document.write( "/3
\n" ); document.write( "2x+30=2490/3\r
\n" ); document.write( "\n" ); document.write( "2x+30=830
\n" ); document.write( "2x=800
\n" ); document.write( "x=400\r
\n" ); document.write( "\n" ); document.write( "rate of the jets 400 & 430 mph
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