document.write( "Question 818053: Three numbers are such the second is two less than twice the first, and the third is three less than twice the second. When six times the difference between the third and the second is subtracted from ten times the difference between the second and the first, the result is the same as twice the difference between the third and the first. \n" ); document.write( "

Algebra.Com's Answer #492331 by mananth(16946) $\"\"$ $\"About$

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Three numbers are such the second is two less than twice the first, and the third is three less than twice the second. When six times the difference between the third and the second is subtracted from ten times the difference between the second and the first, the result is the same as twice the difference between the third and the first. \r
\n" ); document.write( "\n" ); document.write( "let first number be x
\n" ); document.write( "second number = 2x-2\r
\n" ); document.write( "\n" ); document.write( "third = 2(2x-2)-3
\n" ); document.write( "=4x-7\r
\n" ); document.write( "\n" ); document.write( "10((2x-2)-x))- 6((4x-7)-(2x-2))=2(4x-7-x)\r
\n" ); document.write( "\n" ); document.write( "10(x-2)-6(2x-5)=2(3x-7)\r
\n" ); document.write( "\n" ); document.write( "10x-20-12x+30=6x-14\r
\n" ); document.write( "\n" ); document.write( "-8x=-24\r
\n" ); document.write( "\n" ); document.write( "x=3\r
\n" ); document.write( "\n" ); document.write( "3,4,5 are the numbers \n" ); document.write( "

\n" );