document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=817774>Question 817774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 2 liters of 14% solution. He has 10% solution and a 20% solution to form this mixture. How much of each should he use to get the mixture? <BR>\n" );
document.write( "I have already found that he needs 0.8 liters of the 20% solution, I can't seem to get the first one. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492258 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y = 2<BR>\n" );
document.write( ".10x +.20y = 2*.14 = .28<BR>\n" );
document.write( "solve fist equation for x and substitute in second equation<BR>\n" );
document.write( ".10*(2 -y) +.20y = .28<BR>\n" );
document.write( ".20 -.10y + .2oy = .28<BR>\n" );
document.write( ".10y = .08<BR>\n" );
document.write( "y = .8 and x = 1.2<BR>\n" );
document.write( "so we need .8 liters of the 20% solution and 1.2 liters of the 10% solution<BR>\n" );
document.write( "check the answers by substituting in the second equation<BR>\n" );
document.write( ".10*1.2 +.20*.8 = .28<BR>\n" );
document.write( ".12 + .16 = .28<BR>\n" );
document.write( ".28 = .28<BR>\n" );
document.write( "answers check<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );