document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=817782>Question 817782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Any assistance is greatly appreciated in advance.\r<BR>\n" );
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document.write( "Q: Write a system of two equations in two variables to solve the problem.<BR>\n" );
document.write( "A woman invested some money at 8% and some at 9% annual simple interest. The interest for 1 year on the combined investment of $10,000 was $880. How much was invested at each rate?\r<BR>\n" );
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document.write( "8% annual interest $ _____________\r<BR>\n" );
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document.write( "9% annual interest $ _____________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492253 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y = 10000<BR>\n" );
document.write( ".08x +.09y = 880<BR>\n" );
document.write( "solve first equation for x and substitute in second equation<BR>\n" );
document.write( ".08(10000-y) +.09y = 880<BR>\n" );
document.write( "800 -.08y +.09y = 880<BR>\n" );
document.write( ".01y = 80<BR>\n" );
document.write( "y = 8000<BR>\n" );
document.write( "therefore,<BR>\n" );
document.write( "$2000 was invested at 8% and $8000 was invested at 9%<BR>\n" );
document.write( "check the answers<BR>\n" );
document.write( ".08*2000 +.09*8000 = 880<BR>\n" );
document.write( "160 + 720 = 880<BR>\n" );
document.write( "880 = 880<BR>\n" );
document.write( "answers check<BR>\n" );
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