document.write( "Question 817827: Square root of 8 plus 3 times the square root of 8 minus 3
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Algebra.Com's Answer #492207 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"sqrt%288%29%2B3sqrt%288%29-3\"$
\n" ); document.write( "The two square root terms are like terms. (Like radical terms are the same type of root and have the same radicands. (\"Radicand\" is the name for the expression inside a radical.) Our radicals are both square roots with radicands of 8 so we can add them together. Exactly like x + 3x = 4x, $\"sqrt%288%29%2B3sqrt%288%29+=+4sqrt%288%29\"$ . After adding our expression is:
\n" ); document.write( " $\"4%2Asqrt%288%29-3\"$

\n" ); document.write( "All that is left is to simplify the square root. 8 has a perfect square factor, 4, so it will simplify:
\n" ); document.write( " $\"4%2Asqrt%284%2A2%29-3\"$
\n" ); document.write( " $\"4%2Asqrt%284%29%2Asqrt%282%29-3\"$
\n" ); document.write( " $\"4%2A2%2Asqrt%282%29-3\"$
\n" ); document.write( "which simplifies to:
\n" ); document.write( " $\"8%2Asqrt%282%29-3\"$ \r
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