document.write( "Question 817753: Could someone explain to me how to solve:
\n" ); document.write( "\"+%283%29%2F%28x%2B2%29%2B%281%29%2F%28x-2%29=%287%29%2F%28x%5E2-4%29+\"\r
\n" ); document.write( "\n" ); document.write( "I get to: \"+%28%283%29%28x-2%29%2B%281%29%28x%2B2%29%29%2F%28x%2B2%29%28x-2%29=%287%29%2F%28x%5E2-4%29+\"
\n" ); document.write( "Then: \"+%284x-4%29%2F%28x%5E2-4%29+=+7%2F%28x%5E2-4%29+\"
\n" ); document.write( "And: \"+%284x-4%29%28x%5E2-4%29+=+7%28x%5E2-4%29+\"
\n" ); document.write( "Expand: \"+4x%5E3-16x-4x%5E2%2B16+=+7x%5E2-28+\"
\n" ); document.write( "Rearrange: \"+4x%5E3+-11x%5E2-16x%2B44+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "Now I either made a serious mistake somewhere or maybe I just don't know what to do next.
\n" ); document.write( "Equation should have 2 answers
\n" ); document.write( "Thank you
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Algebra.Com's Answer #492172 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"+%284x-4%29%2F%28x%5E2-4%29+=+7%2F%28x%5E2-4%29+\"
\n" ); document.write( "At this point, keeping in mind that \"x=2\" and \"x=-2\" cannot be the final solutions, because they make denominators zero,
\n" ); document.write( "you just solve
\n" ); document.write( "\"4x-4=7\"
\n" ); document.write( "\"4x=11\"
\n" ); document.write( "\"x=11%2F4\"
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\n" ); document.write( "NOTES:
\n" ); document.write( "The denominators in \"+%284x-4%29%2F%28x%5E2-4%29+=+7%2F%28x%5E2-4%29+\"
\n" ); document.write( "are the same on both sides of the equal sign,
\n" ); document.write( "so the numerators have to be the same.
\n" ); document.write( "You could say that you are multiplying both sides of the equation times \"x%5E2-4\"
\n" ); document.write( "to get an equation that is equivalent as long as \"x%5E2-4%3C%3E0\" .
\n" ); document.write( "If you had found \"x=2\" and/or \"x=-2\" as solutions of the transformed equation,
\n" ); document.write( "you would say it is/they are \"extraneous solution(s)\",
\n" ); document.write( "solutions that were introduced by multiplying times \"x%5E2-4\" that are not solutions of the original equation.
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