document.write( "Question 817626: what is the latus rectum of this equation?
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document.write( "y^2-12y+16x+36=0
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document.write( "standard form = (y-6)^2=-16x \n" );
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Algebra.Com's Answer #492163 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! what is the latus rectum of this equation? \n" ); document.write( "y^2-12y+16x+36=0 \n" ); document.write( "standard form = (y-6)^2=-16x \n" ); document.write( "This is an equation of a parabola that opens left \n" ); document.write( "Its basic form of equation: (y-k)^2=4p(x-h) \n" ); document.write( "latus rectum, aka, focal width=4p=16 \n" ); document.write( " |