document.write( "Question 817626: what is the latus rectum of this equation?
\n" ); document.write( "y^2-12y+16x+36=0
\n" ); document.write( "standard form = (y-6)^2=-16x
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Algebra.Com's Answer #492163 by lwsshak3(11628)\"\" \"About 
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what is the latus rectum of this equation?
\n" ); document.write( "y^2-12y+16x+36=0
\n" ); document.write( "standard form = (y-6)^2=-16x
\n" ); document.write( "This is an equation of a parabola that opens left
\n" ); document.write( "Its basic form of equation: (y-k)^2=4p(x-h)
\n" ); document.write( "latus rectum, aka, focal width=4p=16
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