document.write( "Question 817707: [ The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number. ] \n" ); document.write( "
Algebra.Com's Answer #492157 by TimothyLamb(4379)\"\" \"About 
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10b + a = N
\n" ); document.write( "10a + b = N + 27
\n" ); document.write( "10a + b - 27 = N
\n" ); document.write( "---
\n" ); document.write( "a + b = 13
\n" ); document.write( "a = 13 - b
\n" ); document.write( "---
\n" ); document.write( "10b + a = 10a + b - 27
\n" ); document.write( "9b = 9a - 27
\n" ); document.write( "9b = 9(13 - b) - 27
\n" ); document.write( "9b = 117 - 9b - 27
\n" ); document.write( "18b = 90
\n" ); document.write( "---
\n" ); document.write( "b = 5
\n" ); document.write( "a = 8
\n" ); document.write( "---
\n" ); document.write( "N = 58
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