document.write( "Question 817707: [ The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number. ] \n" ); document.write( "
Algebra.Com's Answer #492156 by dkppathak(439)\"\" \"About 
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) The sum of the digits of a two-digit number is 13.When the digits are reversed, the new number is 27 more than the original number.What is the original number.
\n" ); document.write( "let unit digit of number is x
\n" ); document.write( " ten digit of number is 13-x
\n" ); document.write( "number two digit =10xten digit +unit digit
\n" ); document.write( " =10(13-x)+x
\n" ); document.write( " =130-10x+x
\n" ); document.write( " =130-9x
\n" ); document.write( " if digit are reserved ten digit will be x and unit digit will be 13-x
\n" ); document.write( " reverse number will be =10x+13-x
\n" ); document.write( " =9x+13
\n" ); document.write( "as per given condition
\n" ); document.write( "reverse number -27= original number
\n" ); document.write( "9x+13-27=130-9x
\n" ); document.write( "9x+9x=130+14
\n" ); document.write( "18x =144
\n" ); document.write( "x=144/18=8
\n" ); document.write( "unit digit=x=8
\n" ); document.write( "ten digit =13-x=13-8=5
\n" ); document.write( "number =58
\n" ); document.write( "Answer two digit number is 58 \n" ); document.write( "
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