document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=69150>Question 69150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of a rectangle with length, l = 2x + 3 and width, w = 2x - 3<BR>\n" );
document.write( "a. 4x2 <BR>\n" );
document.write( "b. 4x2 - 12x + 9<BR>\n" );
document.write( "c. 4x2 - 9<BR>\n" );
document.write( "d. 4x2 + 9  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49215 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is given by:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+L%2AW ALIGN=MIDDLE  ALT=\"A+=+L%2AW\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substituting L = 2x+3 and W = 2x-3, you get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%282x%2B3%29%282x-3%29 ALIGN=MIDDLE  ALT=\"A+=+%282x%2B3%29%282x-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Perform the indicated multiplication and simplify.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+4x%5E2+-9 ALIGN=MIDDLE  ALT=\"A+=+4x%5E2+-9\"   DISABLED_style= \"max-width:90%; height:auto;\" > ...and you're done! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );