document.write( "Question 817692: A rectangular field is four times as long as it is wide. If the perimeter of the field is 500 feet, what are the dimensions of the field? Recall, perimeter = 2(length) + 2(width). \n" ); document.write( "

Algebra.Com's Answer #492149 by TimothyLamb(4379) $\"\"$ $\"About$

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L = 4w
\n" ); document.write( "2L + 2w = 500
\n" ); document.write( "---
\n" ); document.write( "2L + 2w = 500
\n" ); document.write( "2(4w) + 2w = 500
\n" ); document.write( "8w + 2w = 500
\n" ); document.write( "10w = 500
\n" ); document.write( "---
\n" ); document.write( "w = 50 ft
\n" ); document.write( "L = 200 ft
\n" ); document.write( "---
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