document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=817693>Question 817693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The present age average of a couple & their daughter is 35 years.Fifteen years from now,the age of the mother will be equal to the sum of present ages of the father & the daughter . Find the present age of the mother.<BR>\n" );
document.write( "(A)45 years <BR>\n" );
document.write( "(B)40 years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #492144 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=492144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let father's age be x<BR>\n" );
document.write( "daughter's age be y\r<BR>\n" );
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document.write( "mother's age = z\r<BR>\n" );
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document.write( "(x+y+z)/3= 35\r<BR>\n" );
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document.write( "x+y+z=105<BR>\n" );
document.write( "z= 105-(x+y)\r<BR>\n" );
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document.write( "15 years hence \r<BR>\n" );
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document.write( "105-(x+y)+15 = x+y\r<BR>\n" );
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document.write( "120-x-y=x+y\r<BR>\n" );
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document.write( "2x+2y=120<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x+y=60<BR>\n" );
document.write( "z= 105-60<BR>\n" );
document.write( "z= 45 mothers age </SPAN>\n" );
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