document.write( "Question 817015: Kiana's average test score after 3 tests was 89%. After the 4th test her average raised to 91%. What was Karina's score on the 4th test? \n" ); document.write( "
Algebra.Com's Answer #492128 by FightinBlueHens(27)\"\" \"About 
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The first 3 tests that Kiana took, when divided by 3, gives you an average of 89, so if you multiply 89 by 3, you'll find Kiana's score for the first 3 tests added together.
\n" ); document.write( "You need to find what percent Kiana got on her 4th test so you can divide it by 4, to get the new average, which is 91.
\n" ); document.write( "So if the total score after 3 tests is 89x3, that is 267.
\n" ); document.write( "267+y is the total score of Kiana's 4 tests.
\n" ); document.write( "(267+y)/4 is the average of the 4 tests Kiana took, and we know that that's 91, so
\n" ); document.write( "(267+y)/4=91, so you just have to solve for y, which is her new score.
\n" ); document.write( "267+y=91*4
\n" ); document.write( "91*4=364
\n" ); document.write( "267+y=364
\n" ); document.write( "y=97
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