document.write( "Question 817549: Word problem. 2/3 red beads, 1/4 yellow and rest blue. there are 42 more red beads than blue beads. How many altogether? Here is what I have done.
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\n" ); document.write( "2/3=8/12 1/4=3/12 8/12 + 3/12= 11/12 then I did, 42 divided by 12 = 3.6 \r
\n" ); document.write( "\n" ); document.write( " Now what? I am so confused and hate this. Thank you for your help!
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\n" ); document.write( " Isobelle
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Algebra.Com's Answer #492111 by LinnW(1048)\"\" \"About 
You can put this solution on YOUR website!
r = number of red
\n" ); document.write( "b = number of blue
\n" ); document.write( "y = number of yellow
\n" ); document.write( "r = b + 42 or b = r - 42 and I suppose r - b = 42\r
\n" ); document.write( "\n" ); document.write( "Fraction that are blue
\n" ); document.write( "1 - ( 2/3 + 1/4 )
\n" ); document.write( "1 - ( 8/12 + 3/12 )
\n" ); document.write( "1 - ( 11/12 )
\n" ); document.write( "b = 1/12\r
\n" ); document.write( "\n" ); document.write( "Since y is 1/4 and y = 3/12, y = 3b
\n" ); document.write( "Since r is 2/3 and r = 8/12, r = 8b\r
\n" ); document.write( "\n" ); document.write( "Combine r = b + 42 with r = 8b
\n" ); document.write( "This means that b + 42 = 8b
\n" ); document.write( "Subtract b from each side
\n" ); document.write( " 42 = 7b
\n" ); document.write( " 6 = b
\n" ); document.write( "So we have b = 6 , y = 3b and r = 8b
\n" ); document.write( "Since b + y + r = total
\n" ); document.write( "By substituting
\n" ); document.write( " 6 + 3(6) + 8(6) = total
\n" ); document.write( " 6 + 18 + 48 = 72\r
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