document.write( "Question 817411: im stuck on this problem \r
\n" ); document.write( "\n" ); document.write( "Given that sin theta = .6820 and that theta is in quadrant I. find cos theta/2?
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Algebra.Com's Answer #492048 by lwsshak3(11628)\"\" \"About 
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Given that sin theta = .6820 and that theta is in quadrant I. find cos theta/2?
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\n" ); document.write( "\"cos%28x%2F2%29=sqrt%28%281%2Bcos%28x%29%29%2F2%29\"
\n" ); document.write( "cos(x)=√(1-sin^2x)=√(1-(.682)^2)≈√(1-.4651)≈√.5349≈.7314
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\n" ); document.write( "calculator check:
\n" ); document.write( "sin(x)=.6820
\n" ); document.write( "x≈43˚
\n" ); document.write( "x/2≈21.5˚
\n" ); document.write( "cos(x/2)≈cos(21.5˚)≈0.9304
\n" ); document.write( "value as calculated≈0.9304
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