document.write( "Question 817404: Pure acid is to be added to a 10% acid solution to obtain 90L on 20% solution. What amounts of each should be used?
\n" ); document.write( "How many liters of 100% pur acid should be used?
\n" ); document.write( "H0w many liters of the 10% soultion should be in the mixture?
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Algebra.Com's Answer #492043 by josgarithmetic(39617)\"\" \"About 
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Let u = liters of the 10% acid.
\n" ); document.write( "Let v = liters of the 100% acid.\r
\n" ); document.write( "\n" ); document.write( "You did not say if the percents are as v/v or as w/v, so this solution guidance assumes v/v.\r
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\n" ); document.write( "\n" ); document.write( "Amount of acid =\"10u%2B100v\", and represents 100 times the actual amount of acid, because the percents are used;\r
\n" ); document.write( "\n" ); document.write( "Amount of resulting solution is 90 liters.
\n" ); document.write( "You wanted 20% acid as a result:\r
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\n" ); document.write( "\n" ); document.write( "\"%2810v%2B100v%29%2F90=20\" and \"u%2Bv=90\"
\n" ); document.write( "Solve the system.
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