document.write( "Question 817167: log(5)k - log(5)k-1 = 1 \n" ); document.write( "
Algebra.Com's Answer #492004 by LinnW(1048)\"\" \"About 
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\n" ); document.write( "log(5)k - log(5)k-1 = 1
\n" ); document.write( "log(5)(k/(k-1) = 1
\n" ); document.write( "Notice that 1 = log(5)
\n" ); document.write( "so, log(5)(k/(k-1) = log(5)
\n" ); document.write( "and k/(k-1) = 5
\n" ); document.write( " k/(k-1) = 5/1
\n" ); document.write( "finding cross products
\n" ); document.write( " k = 5(k-1)
\n" ); document.write( " k = 5k -5
\n" ); document.write( " -4k = -5
\n" ); document.write( " k = 5/4 \n" ); document.write( "
\n" );