document.write( "Question 817316: Please help me figure this out. log(base7)x - log(base7)(3x-5)=1 \n" ); document.write( "
Algebra.Com's Answer #492002 by LinnW(1048)\"\" \"About 
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log(base7)(7) = 1, think 7^1 = 7\r
\n" ); document.write( "\n" ); document.write( "so log(base7)(x) - log(base7)(3x-5) = log(base7)(7)\r
\n" ); document.write( "\n" ); document.write( "Since in general log(u/v) = log(u) - log(v)\r
\n" ); document.write( "\n" ); document.write( " log(base7)( x / (3x-5) ) = log(base7)(7)
\n" ); document.write( "So x / (3x-5) = 7/1
\n" ); document.write( " x = 7(3x-5)
\n" ); document.write( " x = 21x -35
\n" ); document.write( " -20x = -35
\n" ); document.write( " x = 35/20
\n" ); document.write( " x = 7/4
\n" ); document.write( " \n" ); document.write( "
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