document.write( "Question 817218: The dimensions of rectangle B are twice the dimensions of rectangle A. The area of rectangle B is 512cm2.\r
\n" ); document.write( "\n" ); document.write( "What is the area of rectangle A?
\n" ); document.write( "

Algebra.Com's Answer #491947 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,\r
\n" ); document.write( "\n" ); document.write( "The dimensions of rectangle B are twice the dimensions of rectangle A.
\n" ); document.write( "The area of rectangle B is 512cm2.
\n" ); document.write( "
\n" ); document.write( "\"A%5BA%5D+=+lw\", \"A%5BB%5D+=+2l%2A2w+=+4lw\"
\n" ); document.write( "Rectangle B has 4 times the Area as Rectangle A
\n" ); document.write( "Rectangle A has a area = \"512cm%5E2%2F4+=+128cm%5E2\" \n" ); document.write( "
\n" );